(a) The film appears bright when the path difference
$(2\mu\ t\cos{r)}$ is equal to odd multiple of $\frac{\lambda}{2}$
$i.e.\ 2\mu t\cos r = (2n - 1)\lambda/2$ where $n = 1,\ 2,\ 3\ldots$
$\therefore\lambda = \frac{4\mu t\cos r}{(2n - 1)}$
$= \frac{4 \times 1.4 \times 10,000 \times 10^{- 10} \times \cos 0}{(2n - 1)} = \frac{56000}{(2n - 1)}\mathring{\mathrm{A}}$
$\therefore\lambda = 56000\mathring{\mathrm{A}},\ 18666\mathring{\mathrm{A}},\ 11200\mathring{\mathrm{A}},\ 8000\mathring{\mathrm{A}},\ 6222\mathring{\mathrm{A}},\ 5091\mathring{\mathrm{A}},\ 4308\mathring{\mathrm{A}},\ 3733\mathring{\mathrm{A}}$
The wavelength which are not within specified range are to be refracted