Q. In a single slit diffraction of light of wavelength $\lambda$ by a slit of width $e$, the size of the central maximum on a screen at a distance $b$ is

A) $2b\lambda + e$
B) $\frac{2b\lambda}{e}$
C) $\frac{2b\lambda}{e} + e$
D) $\frac{2b\lambda}{e} - e$
Explanation

(c) The direction in which the first minima occurs is $\theta$ (say). Then $e\sin\theta = \lambda$ or $e\theta = \lambda$ or, $\theta = \frac{\lambda}{e}$
$(\because\theta = \sin\theta\ $when$\ \theta\ $small)
Width of the central maximum $= 2b\theta + e = 2b.\frac{\lambda}{e} + e$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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