Q. If the two waves represented by $y_{1} = 4\ \sin{\omega t}$ and $y_{2} = 3\sin(\omega t + \pi/3)$ interfere at a point, the amplitude of the resulting wave will be about

A) 7
B) 5
C) 6
D) 3.5
Explanation

(c) $y_{1} = 4\sin{\omega t}$
$y_{2} = 3\sin(\omega t + \pi/3)$
Here, $a = 4,b = 3,\phi = \pi/3$
$R = \sqrt{a^{2} + b^{2} + 2ab\cos\phi}$
$= \sqrt{4^{2} + 3^{2} + 2 \times 4 \times 3\cos{\pi/3}}$
$= \sqrt{37} = 6$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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