Q. The Brewster angle for the glass-air interface is $54.74{^\circ}$. If a ray of light going from air to glass strikes at an angle of incidence $45{^\circ}$, then the angle of refraction is (Hint : $\tan{54.74{^\circ} = \sqrt{2}}$)
A) $60{^\circ}$
B) $30{^\circ}$
C) $25{^\circ}$
D) $54.74{^\circ}$
Explanation
(b) $\mu = \tan i_{p} = \tan{54.74{^\circ} = \sqrt{2}}$
$\because\sqrt{2} = \frac{\sin{40{^\circ}}}{\sin r}$
$\Rightarrow \sin{r = \frac{1}{2} \Rightarrow r = 30{^\circ}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.