(b) Position of $n^{th}$ minima $y_{n} = \frac{n \times D}{d}$
$\Rightarrow y_{3} - y_{1} = \frac{D}{d}(3\lambda - \lambda) = \frac{2\lambda D}{d}$
$\Rightarrow 3 \times 10^{- 3} = \frac{2 \times 6000 \times 10^{- 10} \times 0.5}{d}$
$\Rightarrow d = 0.2 \times 10^{- 3}m = 0.2mm$