Q. A screen is placed $50cm$ from a single slit, which is illuminated with $6000\mathring{\mathrm{A}}$ light. If distance between the first and third minima in the diffraction pattern is $3mm$, the width of the slit is

A) $0.1mm$
B) $0.2mm$
C) $0.3mm$
D) $0.4mm$
Explanation

(b) Position of $n^{th}$ minima $y_{n} = \frac{n \times D}{d}$
$\Rightarrow y_{3} - y_{1} = \frac{D}{d}(3\lambda - \lambda) = \frac{2\lambda D}{d}$
$\Rightarrow 3 \times 10^{- 3} = \frac{2 \times 6000 \times 10^{- 10} \times 0.5}{d}$
$\Rightarrow d = 0.2 \times 10^{- 3}m = 0.2mm$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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