A single slit of width d is illuminated by violet light of wavelength 400 nm and the width of the diffraction patter is measured as $y.$ When half of the slit width is covered and illuminated by yellow light of wavelength 600 nm, the width of the diffraction pattern is

Question

Dr. Abubacker · Accepted Answer

(b) In simple slit diffraction experiment, width of central maxima
$y = \frac{2\lambda D}{d}$
$	herefore\frac{y_{1}}{y_{2}} = \frac{\lambda_{1}}{\lambda_{2}} 	imes \frac{d_{2}}{d_{1}}$
$= \frac{400}{600} 	imes \frac{d/2}{d} = \frac{1}{3}$
$y_{2} = 3y_{1}$

Q. A single slit of width d is illuminated by violet light of wavelength 400 nm and the width of the diffraction patter is measured as $y.$ When half of the slit width is covered and illuminated by yellow light of wavelength 600 nm, the width of the diffraction pattern is

Explanation

Reviewed by Dr. Abubacker

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