Q. Critical angle for certain medium is $\sin^{- 1}{(0.6).\ }$ The polarizing angle of that medium is
A) $\tan^{- 1}\lbrack 1.5\rbrack$
B) $\sin^{- 1}\lbrack 0.8\rbrack$
C) $\tan^{- 1}\lbrack 1.6667\rbrack$
D) $\tan^{- 1}\lbrack 0.6667\rbrack$
Explanation
(c) Critical angle, $C = \sin^{- 1}(0.6)$
$\ \ \ \ \sin{(C) = 0.6}$
$\ \ \mu = \frac{1}{\sin C} = \frac{1}{0.6}$
Polarizing angle $i_{p} = \tan^{- 1}{(\mu)} = \tan^{- 1}\left( \frac{1}{0.6} \right)$
$= \tan^{- 1}(1.6667)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.