Q. In Young’s double slit experiment, the interference pattern is found to have an intensity ratio between bright and dark fringes is 9, this implies that

A) The intensities at the screen due to two slits are 5 units and 4 units respectively
B) The intensities at the screen due to the two slits are 4 units and 1 units, respectively
C) The amplitude ratio is 7
D) The amplitude ratio is 6
Explanation

(b) Given, $\frac{I_{\max}}{I_{min\ }} = 9 = \frac{\left( a_{1} + a_{2} \right)^{2}}{\left( a_{1} - a_{2} \right)^{2}}$
$\therefore\frac{a_{1} + a_{2}}{a_{1} - a_{2}} = 3$
Or $\ 2a_{1} = 4a_{2}$
Or $\ \ a_{1} = 2a_{2}$
$\Rightarrow \frac{a_{1}}{a_{2}} = 2$
Again, intensity ratio at the screen due to two slits
$\frac{I_{1}}{I_{2}} = \frac{a_{1}^{2}}{a_{2}^{2}} = \frac{4}{1}$
Hence, amplitude ratio is 2 and intensities at the screen due to two slits are 4 units and 1 unit, respectively.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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