Q. In Young’s double slit experiment, the distance between the slits is $1\ mm$ and that between slit and screen is 1 meter and 10th fringe is $5\ mm$ away from the central bright fringe, then wavelength of light used will be
A) $5000\ \mathring{\mathrm{A}}$
B) $6000\ \mathring{\mathrm{A}}$
C) $7000\ \mathring{\mathrm{A}}$
D) $8000\ \mathring{\mathrm{A}}$
Explanation
(a) By using $x_{n} = \frac{n\lambda D}{d}$
$\Rightarrow \left( 5 \times 10^{- 3} \right) = \frac{10 \times \lambda \times 1}{(1 \times 10^{- 3})} \Rightarrow \lambda = 5 \times 10^{- 7}m = 5000\mathring{\mathrm{A}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.