Q. If the amplitude ratio of two sources producing interference is 3 : 5, the ratio of intensities at maxima and minima is
A) 25 : 16
B) 5 : 3
C) 16 : 1
D) 25 : 9
Explanation
(c) $\frac{a_{1}}{a_{2}} = \frac{3}{5}$
$\therefore\frac{I_{\max}}{I_{\min}} = \frac{\left( a_{1} + a_{2} \right)^{2}}{\left( a_{1} - a_{2} \right)^{2}} = \frac{(3 + 5)^{2}}{(3 - 5)^{2}} = \frac{16}{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.