Q. Which of the following diagrams represent the variation of electric field vector with time for a circularly polarized light
A) [image:10_image19.emf]
B) [image:10_image20.emf]
C) [image:10_image21.emf]
D) [image:10_image22.emf]
Explanation
(a) To form circularly polarized light
$E_{x} = A\sin{\omega t}$
$E_{y} = A\cos{\omega t}$
Resultant amplitude
$\left| \overrightarrow{E} \right|^{2} = A^{2} + A^{2} + 2A.A\cos\frac{\pi}{2} \Rightarrow \left| \overrightarrow{E} \right| = A\sqrt{2}$
= constant
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.