Q. In a Young’s double slit experiment, the fringe width is found to be $0.4\ mm$. If the whole apparatus is immersed in water of refractive index $4/3$ without disturbing the geometrical arrangement, the new fringe width will be
A) $0.30\ mm$
B) $0.40\ mm$
C) $0.53\ mm$
D) $450\ micron$
Explanation
(a) $\beta_{water} = \frac{B_{air}}{\mu} = \frac{0.4}{4/3} = 0.3mm$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.