Q. Young’s double slit experiment is carried out by using green, red and blue light, one color at a time. The fringe widths recorded are $\beta_{G},\beta_{R}$ and $\beta_{B}$, respectively. Then
A) $\beta_{G} > \beta_{B} > \beta_{R}$
B) $\beta_{B} > \beta_{G} > \beta_{R}$
C) $\beta_{R} > \beta_{B} > \beta_{G}$
D) $\beta_{R} > \beta_{G} > \beta_{B}$
Explanation
(d) $\beta = \frac{\lambda D}{d}$
$\overrightarrow{VIBGYOR}\lambda$ increases
$\lambda_{R} > \lambda_{G} > \lambda_{B}$
So $\beta_{R} > \beta_{G} > \beta_{B}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.