Q. Red light of wavelength $625\ nm$ is incident normally on an optical diffraction grating with $2 \times 10^{5}lines/m$. Including central principal maxima, how many maxima may be observed on a screen which is far from the grating

A) 15
B) 17
C) 8
D) 16
Explanation

(b) Here, wavelength, $\lambda = 625nm = 625 \times 10^{- 9}m$
Number of lines per meter, $N = 2 \times 10^{5}$
For principal maxima is grating spectra $\frac{\sin\theta}{N} = n\lambda$,
Where $n( = 1,2,3)$ is the order of principal maxima and $\theta$ is the angle of diffraction
The maximum value of $\sin\theta$ is 1
$\therefore n = \frac{1}{N\lambda} = \frac{1}{2 \times 10^{5} \times 625 \times 10^{- 9}} = 8$
$\therefore$ Number of maxima $= 2n + 1 = 2 \times 8 + 1 = 17$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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