Q. A light has amplitude $A$ and angle between analyser and polarizer is $60{^\circ}$. Light is reflected by analyser has amplitude
A) $A\sqrt{2}$
B) $A/\sqrt{2}$
C) $\sqrt{3}A/2$
D) $A/2$
Explanation
(d) The amplitude will be $A\cos{60{^\circ} = A/2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.