Q. There are $n_{1}$ photons of frequency $v_{1}$ in a beam of light. In an equally energetic beam there are $n_{2}$ photons of frequency $v_{2}$. Then the correct relation
A) $\frac{n_{1}}{n_{2}} = \frac{v_{1}}{v_{2}}$
B) $\frac{n_{1}}{n_{2}} = 1$
C) $\frac{n_{1}}{n_{2}} = \frac{v_{2}}{v_{1}}$
D) $\frac{n_{1}}{n_{2}} = \frac{v_{2}^{2}}{v_{1}^{2}}$
Explanation
(c) Here, $E_{1} = E_{2}$
$\ n_{1}hv_{1} = n_{2}hv_{2}$
So, $\frac{n_{1}}{n_{2}} = \frac{v_{2}}{v_{1}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.