Q. If particles are moving with same velocity, then maximum de-Bronglie wavelength will be for
A) Neutron
B) Proton
C) $\beta$-particle
D) $\alpha$-particle
Explanation
(c) $\lambda = \frac{h}{mv} \Rightarrow \lambda \propto \frac{1}{m}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.