Q. In the experiment for the determination of $\frac{e}{m}$ of electrons by the Thomson method, electric and magnetic fields are
A) Parallel and both are perpendicular to the motion of the electron
B) Both mutually perpendicular and parallel to the motion of electron
C) Both mutually perpendicular and also perpendicular to the motion of electron
D) Both mutually perpendicular and have no relation with motion of the electron
Explanation
(c) In Thomson’s experiment to determine the charge to mass ratio of an electron, his apparatus was as follows
[image:11_image34.emf]
A uniform magnetic field is created between X and Y, by applying a potential difference between them. In the same region and outside the tube is placed an electromagnet which produces a magnetic field perpendicular to the plane of paper. Thus, two fields are produced in the same region perpendicular to each other, also the two fields are perpendicular to the motion of electron.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.