The $K_{\alpha}\ X$-rays arising from a cobalt ($z = 27$) target have a wavelength of $179\ pm.$ The $K_{\alpha}\ X$-rays arising from a nickel target ($z = 28$) is

Question

Dr. Abubacker · Accepted Answer

(b) $\lambda_{k\alpha} \propto \frac{1}{(Z - 1)^{2}} \Rightarrow \frac{\lambda_{Ni}}{\lambda_{Co}} = \left( \frac{Z_{Co} - 1}{Z_{Ni} - 1} ight)^{2} = \left( \frac{27 - 1}{28 - 1} ight)^{2}$
$\Rightarrow \lambda_{Ni} = \left( \frac{26}{27} ight)^{2} 	imes \lambda_{Co} = \left( \frac{26}{27} ight)^{2} 	imes 179 = 165.9\ pm < 179pm$

Q. The $K_{\alpha}\ X$-rays arising from a cobalt ($z = 27$) target have a wavelength of $179\ pm.$ The $K_{\alpha}\ X$-rays arising from a nickel target ($z = 28$) is

Explanation

Reviewed by Dr. Abubacker

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