(c) $W_{0} = \frac{hc}{\lambda_{0}} = \frac{6.625 \times 10^{- 34} \times 3 \times 10^{8}}{5000 \times 10^{- 10}}J = 4 \times 10^{- 19}J$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.