The cathode of a photoelectric cell is changed such that the work function changes from $W_{1}$ to $W_{2}\left( W_{2} W_{1} \right).$ If the current before and after change are $I_{1}$ and $I_{2},$ all other conditions remaining unchanged, then (assuming $hv W_{2}$)

Question

The cathode of a photoelectric cell is changed such that the work function changes from $W_{1}$ to $W_{2}\left( W_{2} > W_{1} \right).$ If the current before and after change are $I_{1}$ and $I_{2},$ all other conditions remaining unchanged, then (assuming $hv > W_{2}$)

Dr. Abubacker · Accepted Answer

(a) The work function has no effect on current so long as $hv > W_{0}.$ The photoelectric current is proportional to the intensity of light. Since there is no change in the intensity of light, therefore $I_{1} = I_{2}$

Q. The cathode of a photoelectric cell is changed such that the work function changes from $W_{1}$ to $W_{2}\left( W_{2} > W_{1} \right).$ If the current before and after change are $I_{1}$ and $I_{2},$ all other conditions remaining unchanged, then (assuming $hv > W_{2}$)

Explanation

Reviewed by Dr. Abubacker

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