Q. The correct graph between the maximum energy of a photoelectron and the inverse of wavelength of the incident radiation is given by the curve
A) $A$
B) $B$
C) $C$
D) None of the above
Explanation
(a) $K_{max\ } = hv - hv_{0} = \frac{hc}{\lambda} - \frac{hc}{\lambda_{0}},\ i.e.,$ graph between $K_{\max}$ and $\frac{1}{\lambda}$ will be straight line having slope $(hc)$ and intercept $\frac{hc}{\lambda_{0}}$ on $- KE$ axis
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.