Q. The correctness of velocity of an electron moving with velocity $50\ ms^{- 1}$ is 0.005%. The accuracy with which its position can be measured will be
A) $4634 \times 10^{- 3}m$
B) $4634 \times 10^{- 5}m$
C) $4634 \times 10^{- 6}m$
D) $4634 \times 10^{- 8}m$
Explanation
(b) Here, $\Delta v = \frac{0.005 \times 50}{100} = 0.0025ms^{- 1}$
$\Delta x = \frac{h}{m\Delta v}$
$= \frac{1.034 \times 10^{- 34}}{9.1 \times 10^{- 31} \times 0.0025} = 4634 \times 10^{- 5}m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.