Q. If the uncertainty in the position of proton is $6 \times 10^{8}$m, then the minimum uncertainty in its speed will be
A) $1\ cms^{- 1}$
B) $1\ ms^{- 1}$
C) $1\ mms^{- 1}$
D) $100\ ms^{- 1}$
Explanation
(b) $\Delta p = m\Delta v = \frac{\hslash}{\Delta x}$
or $\Delta v = \frac{\hslash}{m\Delta x} = \frac{1.034 \times 10^{- 34}}{1.67 \times 10^{- 27} \times 6 \times 10^{- 8}}$
$\approx 1ms^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.