Q. An electron and a proton are moving in the same direction with same kinetic energy. The ratio of the de- Broglie wavelength associated with these particles is
A) $\frac{m_{e}}{m_{p}}$
B) $\frac{m_{p}}{m_{e}}$
C) $\sqrt{\frac{M_{p}}{M_{e}}}$
D) $m_{p}.m_{e}$
Explanation
(c) de-Broglie wavelength
Here $\lambda_{e} = \frac{h_{c}}{\sqrt{2m_{e}\ E}}\ $and $\lambda_{p} = \frac{h_{c}}{\sqrt{2m_{p}\ E}}$
$\frac{\lambda_{e}}{\lambda_{p}} = \sqrt{\frac{m_{p}}{m_{e}}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.