(b) $hc/\lambda\ = 10^{3}\ eV$ …(i) $hv = 10^{6}eV$ …(ii) Dividing Eq.(ii) by Eq. (i) we get, $v = 10^{3}c/\lambda$ $= 10^{3} \times 3 \times 10^{8}/1.24 \times 10^{- 9} = 2.4 \times 10^{20}$Hz
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