Q. Photon and electron are given energy ${(10}^{- 2}J)$. Wavelengths associated with photon and electron are $\lambda_{ph}$and $\lambda_{el}$ then, correct statement will be
A) $\lambda_{ph} > \lambda_{el}$
B) $\lambda_{ph} < \lambda_{el}$
C) $\lambda_{ph} = \lambda_{el}$
D) $\frac{\lambda_{el}}{\lambda_{ph}} = c$
Explanation
(a) Wavelength of photon will be greater than that of electron because mass of photon is less than that of electron
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \lambda_{ph} > \ \lambda el$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.