Q. A potential difference of $42,000\ volts$ is used in an $X$-ray tube to accelerate electrons. The maximum frequency of the $X$-raditions produced is
A) $10^{19}Hz$
B) $10^{18}Hz$
C) $10^{16}Hz$
D) $10^{20}Hz$
Explanation
(a) $hv_{\max} = eV\ \therefore v_{\max} = \frac{eV}{h} = \frac{1.6 \times 10^{- 19} \times 42000}{6.63 \times 10^{- 34}} = 10^{19}Hz$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.