Q. In an electron gun, the electrons are accelerated by the potential $V.$ If $e$ is the charge and $m$ is the mass of an electron, then maximum velocity of these electron will be
A) $\frac{2eV}{m}$
B) $\sqrt{\frac{2eV}{m}}$
C) $\sqrt{\frac{2m}{eV}}$
D) $\frac{V^{2}}{2em}$
Explanation
(b) $eV = \frac{1}{2}mv^{2} \Rightarrow v^{2} = \frac{2eV}{m} \Rightarrow v = \sqrt{\frac{2eV}{m}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.