Q. If $V$ be the accelerating voltage, then the maximum frequency of continuous $X$-rays is given by
A) $\frac{eh}{V}$
B) $\frac{hV}{e}$
C) $\frac{eV}{h}$
D) $\frac{h}{eV}$
Explanation
(c) $E = eV = hv_{\max} \Rightarrow v_{\max} = \frac{eV}{h}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.