Q. Work function of a metal is $2.51\ eV.$ Its threshold frequency

A) $5.9 \times 10^{14}cycles/s$
B) $6.5 \times 10^{14}cycles/s$
C) $9.4 \times 10^{14}cycles/s$
D) $6.08 \times 10^{14}cycles/s$
Explanation

(d) $W_{0} = hv_{0} \Rightarrow v_{0} = \frac{W_{0}}{h} = \frac{2.51 \times 1.6 \times 10^{- 19}}{6.6 \times 10^{- 34}}$
$= 6.08 \times 10^{14}\ Cycles/s$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.