An X-ray tube with a copper target emits $K_{\alpha}$ line of wavelength $1.50\ \mathring{\mathrm{A}}.$ What should be the minimum voltage through which electrons are to be accelerated to produce this wavelength of $X$ rays $(h = 6.63 imes 10^{- 34}J$-$s,\ c = 3 imes 10^{8}m/s)$

Question

An X-ray tube with a copper target emits $K_{\alpha}$ line of wavelength $1.50\ \mathring{\mathrm{A}}.$ What should be the minimum voltage through which electrons are to be accelerated to produce this wavelength of $X$ rays $(h = 6.63 	imes 10^{- 34}J$-$s,\ c = 3 	imes 10^{8}m/s)$

Dr. Abubacker · Accepted Answer

(a) $eV = \frac{hc}{\lambda} = \frac{6.63 	imes 10^{- 34} 	imes 3 	imes 10^{8}}{1.5 	imes 10^{- 10}}$
$\Rightarrow V = \frac{6.63 	imes 10^{- 34} 	imes 3 	imes 10^{8}}{1.6 	imes 10^{- 19} 	imes 1.5 	imes 10^{- 10}} = 8280\ Volt$

Q. An X-ray tube with a copper target emits $K_{\alpha}$ line of wavelength $1.50\ \mathring{\mathrm{A}}.$ What should be the minimum voltage through which electrons are to be accelerated to produce this wavelength of $X$ rays $(h = 6.63 \times 10^{- 34}J$-$s,\ c = 3 \times 10^{8}m/s)$

Explanation

Reviewed by Dr. Abubacker

Want more practice?