Q. If wavelength of photon and electron is same then ratio of total energy of electron to total energy of photon would be
A) $\frac{Velocity\ of\ electron\ }{{Light}^{'}s\ speed}$
B) $\frac{{Light}^{'}s\ speed}{{Electron}^{'}s\ speed}$
C) $\frac{{Light}^{'}sspeed}{Velocity\ of\ electron}$
D) $\frac{{Electron}^{'}s\ speed}{{Light}^{'}s\ speed}$
Explanation
(a) $E = hv = h.\frac{v}{\lambda} \Rightarrow E \propto v\ \lbrack h\ $and$\ \lambda\ $are constant]
$\frac{E_{ele.}}{E_{photon}} = \frac{v_{ele.}}{C(velocity\ of\ light)}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.