(d) $\because\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \lambda = \frac{h}{p}\ \Rightarrow \lambda \propto \frac{1}{p}$ $ie,\ $when $\lambda$ increases, $p$ decreases.
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.