An X-ray tube produces a continuous spectrum of radiation with its shortest wavelength of $45 imes 10^{- 2}A.$ The maximum energy of a photon in the radiation in eV is ($h = 6.62 imes 10^{- 34}$ Js , $c = 3 imes 10^{8}\ {ms}^{- 1})$

Question

An X-ray tube produces a continuous spectrum of radiation with its shortest wavelength of $45 	imes 10^{- 2}A.$ The maximum energy of a photon in the radiation in eV is ($h = 6.62 	imes 10^{- 34}$ Js , $c = 3 	imes 10^{8}\ {ms}^{- 1})$

Dr. Abubacker · Accepted Answer

(a) $\ \ \ \ \ \ \ \ \ E = \frac{hc}{\lambda}$
= $\frac{6.62 	imes 10^{- 34} 	imes 3 	imes 10^{8}\ }{45 	imes 10^{- 12}}$
= $\frac{0.44 	imes 10^{- 14}}{1.6 	imes 10^{- 19}} = 0.275 	imes 10^{5}$ eV = 27500 eV

Q. An X-ray tube produces a continuous spectrum of radiation with its shortest wavelength of $45 \times 10^{- 2}A.$ The maximum energy of a photon in the radiation in eV is ($h = 6.62 \times 10^{- 34}$ Js , $c = 3 \times 10^{8}\ {ms}^{- 1})$

Explanation

Reviewed by Dr. Abubacker

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