(a) By using $\lambda_{electron} = \frac{h}{m_{e}v} \Rightarrow v = \frac{h}{m_{e}\lambda_{e}}$ $= \frac{6.6 \times 10^{- 34}}{9.1 \times 10^{- 31} \times 10^{- 10}} = 7.25 \times 10^{6}m/s$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.