Q. The potential difference applied to an $X$-ray tube is $5kV$ and the current through it is $3.2\ mA.$ Then the number of electrons striking the target per second is
A) $2 \times 10^{16}$
B) $5 \times 10^{16}$
C) $1 \times 10^{17}$
D) $4 \times 10^{15}$
Explanation
(a) $i = \frac{Ne}{t} \Rightarrow \frac{N}{t} = \frac{i}{e} = \frac{3.2 \times 10^{- 3}}{1.6 \times 10^{- 19}} = 2 \times 10^{16}/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.