If a voltage applied to an $X$-ray tube is increased to 1.5 times the minimum wavelength $(\lambda_{\min})$ of an $X$-ray continuous spectrum shifts by $\Delta\lambda = 26\ pm.$ The initial voltage applied to the tube is

Question

Dr. Abubacker · Accepted Answer

(b) $\lambda_{\min} = \frac{hc}{eV} \Rightarrow \lambda_{1} = \frac{hc}{eV_{1}}\ and\ \lambda_{2} = \frac{hc}{eV_{2}}$
$	herefore\mathrm{\Delta}\lambda = \lambda_{2} - \lambda_{1} = \frac{hc}{e}\left\lbrack \frac{1}{V_{2}} - \frac{1}{V_{1}} ightbrack.$ Given $V_{2} = 1.5\ V_{1}$
on solving we get $V_{1} = 16000\ volt = 16\ kV$

Q. If a voltage applied to an $X$-ray tube is increased to 1.5 times the minimum wavelength $(\lambda_{\min})$ of an $X$-ray continuous spectrum shifts by $\Delta\lambda = 26\ pm.$ The initial voltage applied to the tube is

Explanation

Reviewed by Dr. Abubacker

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