Q. The photons in a radiowave of wavelength $3 \times 10^{4}$ cm have energy
A) $6.62 \times 10^{- 10}$ J
B) $19.86 \times 10^{- 24}$ J
C) $6.62 \times 10^{- 28}$ J
D) $2.2 \times 10^{- 35}$ J
Explanation
(c) Energy of photon, $\ \ E = \frac{hc}{\lambda}$
$= \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{3 \times 10^{2}}$
=$\ 6.6 \times 10^{- 28}J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.