Q. The de-Broglie wavelength of an electron in the ground state of the hydrogen atom is
A) $\pi r^{2}$
B) $2\pi r$
C) $\pi r$
D) $\sqrt{2\pi r}$
Explanation
(b) According to Bohr’s theroy
$mvr = \frac{nh}{2\pi}$
$2\pi r = \frac{nh}{mv}$
$2\pi r - n\lambda$
For n=1,$\lambda = 2\pi r$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.