(b) According to Einstein’s mass energy equivalence
$E = mc^{2}$
$\therefore$ Loss of mass per second $= \frac{(3.77 \times 10^{26})}{c^{2}}kg$
$= \frac{(3.77 \times 10^{26})}{\left( 3 \times 10^{8} \right)^{2}}kg = 0.419 \times 10^{10}kg = 41.9 \times 10^{8}kg$