Q. Nuclear radii may be measured by scattering high energy electrons from nuclei. What is the de-Broglie wavelength for 200 MeV electrons?
A) 8.28 fm
B) 7.98 fm
C) 6.45 fm
D) 6.20 fm
Explanation
(d) The de-Broglie wavelength
$\lambda\ = \frac{hc}{E} = \frac{1240}{200 \times 10^{6}}$
=6.20$\times 10^{- 6}$ nm = 6.20fm
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.