(b) $\ \lambda_{photon} = \ \frac{hc}{E}$
and $\lambda_{electron\ } = \frac{h}{\sqrt{2mE}}\ $
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{\lambda_{photon}}{\ \lambda_{electron}} = c\sqrt{\frac{2m}{E}}\ $
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{\lambda_{photon}}{\ \lambda_{electron}} \propto \frac{1}{\sqrt{E}}\ \ \ \ $