Q. The slope of frequency of incident light and stopping potential graph for a given surface will be
A) $h$
B) $h/e$
C) $eh$
D) $e$
Explanation
(b) The equation of curve between $V_{0}$ and $v$ is $\frac{hv}{e} - \frac{hv_{0}}{e} = V_{0}$
This is equation of a straight line with slope $= \frac{h}{e}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.