(a) $\because m_{e} < m_{p} < m_{\alpha} \Rightarrow \left( \frac{q}{m} \right)_{e} > \left( \frac{q}{m} \right)_{p} > \left( \frac{q}{m} \right)_{\alpha}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.