Q. A positively charged particle enters a magnetic field of value $B\widehat{\mathbf{j}}$ with a velocity $v\widehat{\mathbf{k}}.$ The particle will move along

A) $+ \ X$ axis
B) $- X$ axis
C) $+ \ Z$ axis
D) $- Z$ axis
Explanation

(b) Force on the charged particle in magnetic field is
$\overrightarrow{\mathbf{F}} = q\left( v\widehat{\mathbf{k}} \times B\widehat{\mathbf{j}} \right) = qvB\left( \widehat{\mathbf{k}} \times \widehat{\mathbf{j}} \right) = qvB( - \widehat{\mathbf{i}})$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.