(b) Threshold wavelength for $Na,\ \lambda_{Na} = \frac{12375}{2} = 6187.5\mathring{\mathrm{A}}$ Also$\ \lambda_{Cu} = \frac{12375}{4} = 3093.75$ Since$\ \lambda_{Na} > 4000\mathring{\mathrm{A}};$ So$\ Na\ $is suitable
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