Q. 4 $eV$ is the energy of the incident photon and the work function is $2eV.$ What is the stopping potential
A) $2V$
B) $4V$
C) $6V$
D) $2\sqrt{2}V$
Explanation
(a) $E = W_{0} + eV_{0} \Rightarrow 4eV = 2eV + eV_{0} \Rightarrow V_{0} = 2\ volt$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.