Q. A photocell stops emission if it is maintained at $2V$ negative potential. The energy of most energetic photoelectron is
A) $2eV$
B) $2J$
C) $2kJ$
D) $2keV$
Explanation
(a) $K_{\max} = \left( \left| V_{0} \right| \right)eV = 2eV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.