In a mass spectrograph, an ion $X$ of mass number 24 and charge $+ e$ and another ion $Y$ of mass number 22 and charge $+ \ 2e$ enter in a perpendicular magnetic field with the same velocity. The ratio of the radii of the circular path in the field will be

Question

Dr. Abubacker · Accepted Answer

(d) $r = \frac{mv}{qB}ie,\ r \propto m/q$
So, $\frac{r_{1}}{r_{2}} = \frac{m_{1}}{m_{2}} 	imes \frac{q_{2}}{q_{1}} = \frac{24 	imes 2e}{22 	imes e} = \frac{24}{11}$

Q. In a mass spectrograph, an ion $X$ of mass number 24 and charge $+ e$ and another ion $Y$ of mass number 22 and charge $+ \ 2e$ enter in a perpendicular magnetic field with the same velocity. The ratio of the radii of the circular path in the field will be

Explanation

Reviewed by Dr. Abubacker

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